1846 Vermont gubernatorial election

The 1846 Vermont gubernatorial election took place on September 1, 1846,[1] and resulted in the reelection of Whig Party candidate Horace Eaton to a one-year term as governor.[2]

1846 Vermont gubernatorial election


 1845 September 1, 1846 (1846-09-01) 1847 
 
Nominee Horace Eaton John Smith Lawrence Brainerd
Party Whig Democratic Free Soil
Popular vote 23,644 17,877 7,118
Percentage 48.5% 36.7% 14.6%

Governor before election

William Slade
Whig

Elected Governor

Horace Eaton
Whig Party (United States)

Elections in Vermont
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. . . 1846 Vermont gubernatorial election . . .

In the race for governor, incumbent lieutenant governor Horace Eaton defeated Smith, a former member of the United States House of Representatives and Brainerd, a former member of the Vermont House of Representatives.[3]

In the popular vote for lieutenant governor, Whig Leonard Sargeant defeated Democrat Truman B. Ransom and Free Soil candidate Jacob Scott.[3] The vote totals were: Sargeant, 23,335 (47.4%); Ransom, 17,985 (36.6%); Scott, 7,801 (15.9%); scattering, 65 (0.1%).[3]

The contest for state treasurer resulted in the election of Whig Elisha P. Jewett, who defeated Democrat Daniel Baldwin and Free Soil nominee Zenas Wood.[3] Vote totals in the treasurer’s race were: Jewett, 23,324 (48.2%); Baldwin, 17,847 (36.9%); Wood, 6,978 (14.4%); scattering, 192 (0.5%).[3]

Because none of the popular vote winners achieved the 50 percent required by the Constitution of Vermont, the Vermont General Assembly was required to choose the winners.[3] In most cases, the assembly selects the candidate who received a plurality of the vote.[3] In the October 8, 1846 legislative elections, Eaton, Sargent, and Jewett all won their contests.[3] The reported vote totals were:[3]

. . . 1846 Vermont gubernatorial election . . .

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. . . 1846 Vermont gubernatorial election . . .